Optimal. Leaf size=47 \[ \frac{b \text{PolyLog}\left (2,1-\frac{2 e}{e+f x}\right )}{2 e f}+\frac{(a-b \log (2)) \tanh ^{-1}\left (\frac{f x}{e}\right )}{e f} \]
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Rubi [A] time = 0.0648044, antiderivative size = 47, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.138, Rules used = {2403, 208, 2402, 2315} \[ \frac{b \text{PolyLog}\left (2,1-\frac{2 e}{e+f x}\right )}{2 e f}+\frac{(a-b \log (2)) \tanh ^{-1}\left (\frac{f x}{e}\right )}{e f} \]
Antiderivative was successfully verified.
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Rule 2403
Rule 208
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int \frac{a+b \log \left (\frac{e}{e+f x}\right )}{e^2-f^2 x^2} \, dx &=b \int \frac{\log \left (\frac{2 e}{e+f x}\right )}{e^2-f^2 x^2} \, dx+(a-b \log (2)) \int \frac{1}{e^2-f^2 x^2} \, dx\\ &=\frac{\tanh ^{-1}\left (\frac{f x}{e}\right ) (a-b \log (2))}{e f}+\frac{b \operatorname{Subst}\left (\int \frac{\log (2 e x)}{1-2 e x} \, dx,x,\frac{1}{e+f x}\right )}{f}\\ &=\frac{\tanh ^{-1}\left (\frac{f x}{e}\right ) (a-b \log (2))}{e f}+\frac{b \text{Li}_2\left (1-\frac{2 e}{e+f x}\right )}{2 e f}\\ \end{align*}
Mathematica [A] time = 0.0254576, size = 80, normalized size = 1.7 \[ \frac{2 b^2 \text{PolyLog}\left (2,\frac{e+f x}{2 e}\right )-\left (a+b \log \left (\frac{e}{e+f x}\right )\right ) \left (a+2 b \log \left (\frac{e-f x}{2 e}\right )+b \log \left (\frac{e}{e+f x}\right )\right )}{4 b e f} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.063, size = 109, normalized size = 2.3 \begin{align*} -{\frac{a}{2\,fe}\ln \left ( 2\,{\frac{e}{fx+e}}-1 \right ) }+{\frac{b}{2\,fe}\ln \left ( 1-2\,{\frac{e}{fx+e}} \right ) \ln \left ( 2\,{\frac{e}{fx+e}} \right ) }-{\frac{b}{2\,fe}\ln \left ( 1-2\,{\frac{e}{fx+e}} \right ) \ln \left ({\frac{e}{fx+e}} \right ) }+{\frac{b}{2\,fe}{\it dilog} \left ( 2\,{\frac{e}{fx+e}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, a{\left (\frac{\log \left (f x + e\right )}{e f} - \frac{\log \left (f x - e\right )}{e f}\right )} + b \int \frac{\log \left (f x + e\right ) - \log \left (e\right )}{f^{2} x^{2} - e^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{b \log \left (\frac{e}{f x + e}\right ) + a}{f^{2} x^{2} - e^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{a}{- e^{2} + f^{2} x^{2}}\, dx - \int \frac{b \log{\left (\frac{e}{e + f x} \right )}}{- e^{2} + f^{2} x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{b \log \left (\frac{e}{f x + e}\right ) + a}{f^{2} x^{2} - e^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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